aznxknight Posted November 24, 2016 Posted November 24, 2016 (edited) I'm talking about the treasure loot cards you can get from completing scenarios for the first time. Wand of enervation, sihedron medallion, snakeskin tunic, etc. If so, wouldn't it be pretty gamebreaking to have all your characters have revelation quills, never encounter an unwanted bane again AND find the henchman/villain with at most 6 explores. So i'm guessing no, which is why the sihedron medallions have different scenario numbers to differentiate them. Or does it only apply to some treasure cards? I'm still veering in the direction of no. Edited November 24, 2016 by aznxknight
Ethics Gradient Posted November 24, 2016 Posted November 24, 2016 (edited) Campaign cards (AD1-6, C-deck, Promos) do not have a per-party limit. There are "soft" limits through. If your party has more of a card than normally seen in the game Vault, then that party will not encounter that card on subsequent play-throughs. This shouldn't include loot cards. They should always be rewarded (regardless of inventory) as long as the party has not previously completed the scenario. Treasure cards have "hard" limits. If you attempt to form a party containing more of a treasure card than you have been rewarded, the cards in excess will be removed. Rewards Cards like Guide to the Beyond or Black Arrow Longbow are technically treasure cards (even if they didn't come from a chest); they are subject to the same rules. Yes, it is quite possible to create some bonkers load-outs by forming up a few parties and trading amongst them. For example, I've got an Ezren nicknamed "the Seer" with eight Auguries. Maybe I should upgrade him to Scrying! Edited November 24, 2016 by Ethics Gradient
aznxknight Posted November 24, 2016 Author Posted November 24, 2016 Oh i'm aware of the campaign cards and having multiples but i wasn't sure about treasure cards. Which actually brings me to my next point where I have just encountered the duplication bug. I'll create it in another topic in technical support.
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