February 21, 200421 yr Ok, this is waaaay off topic, but guess that's what these forums are for +_+ A kiss and a candy for anyone who can solve this equation (giving full detail on how he did that): -4x^3+3x-1/2=0
February 21, 200421 yr Use Newton's method (calculus) Basically get an estimate/guess of X (say .2), then keep doing the iteration below (computer recommended for sanity). Xn+1 = Xn- f(Xn)/f'(Xn) f(x) = -4x^3+3x-1/2 f'(x) is the derivative of f(x) Successive X's will be converge to the "real" root (they get more accurate each time), so keep doing it until it's accurate enough for you. Here's a short cut: http://www.math.sc.edu/cgi-bin/sumcgi/Newton.pl Answer: x=0.17364817766693 Edit: Here's an explanation (semi-proof) why Newton's method works. Stop reading just after equation (5), we're not really interested in the rest (and it gets ugly too). Spreading beauty with my katana.
February 24, 200421 yr If i posted some of my uni work could you write some technical reports for me please :D
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